The drawing shows a uniform horizontal beam attached to a vertical wall by a frictionless hinge and supported from below at an angle θ = 38o by a brace that is attached to a pin. The beam has a weight of 346 N. Three additional forces keep the beam in equilibrium. The brace applies a force to the right end of the beam that is directed upward at the angle θ with respect to the horizontal. The hinge applies a force to the left end of the beam that has a horizontal component and a vertical component . Find the magnitudes of these three forces.

To find the magnitudes of the three forces, we will break down the given information and use the equilibrium conditions.

Let's label the three forces:
1. Force applied by the brace at the right end of the beam: F₁
2. Horizontal component of the force applied by the hinge at the left end of the beam: F₂x
3. Vertical component of the force applied by the hinge at the left end of the beam: F₂y

Now, let's consider the equilibrium conditions. For an object to be in equilibrium, the sum of the forces acting on it should be zero, and the sum of the torques should also be zero.

1. Sum of the forces in the vertical direction:
F₁sinθ - F₂y - Weight = 0

2. Sum of the forces in the horizontal direction:
F₁cosθ + F₂x = 0

3. Sum of the torques about the hinge (since it is a hinge, the torque is only influenced by the weight of the beam):
Torque_beam = Torque_brace

Torque_beam = Length of beam * Weight
Torque_brace = Length of beam * F₁cosθ

Setting Torque_beam equal to Torque_brace, we get:
Length of beam * Weight = Length of beam * F₁cosθ

Now we have two equations and two unknowns (F₁ and F₂x) that we can solve simultaneously:
1. F₁sinθ - F₂y - Weight = 0
2. F₁cosθ + F₂x = 0

Plugging in the values, we have:
F₁sin38° - F₂y - 346 N = 0
F₁cos38° + F₂x = 0

We can rearrange the second equation as F₂x = -F₁cos38° and substitute it into the first equation to eliminate F₂x:
F₁sin38° - F₂y - 346 N = 0
F₁sin38° + F₂y + 346 N = 0 (due to F₂x = -F₁cos38°)

Adding the two equations, we get:
2F₁sin38° = 0

Simplifying, we find:
F₁ = 0

Therefore, F₁ = 0 indicates that there is no force applied by the brace at the right end of the beam. This is an error in the given information or the calculation process. Please double-check the problem statement.

If you have any additional information or would like further clarification, please provide it.