posted by .

csc^2 x sec x / sec^2 x + csc^2 x

  • trig -

    sec^2 + csc^2 = 1/cos^2 + 1/sin^2 = (sin^2+cos^2)/(sin^2 cos^2) = 1/(sin^2 cos^2)

    csc^2 sec = 1/(sin^2 cos) = cos/(sin^2 cos^2)

    so , doing the division, we end up with just

    cos x

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. more trig.... how fun!!!!

    if you can't help me with my first question hopw you can help me with this one. sec(-x)/csc(-x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(-x)/csc(-x) = sin(-x)/cos(-x) …
  2. trig

    Ok so I have a right triangle with the hypothenuse = to 5, one side =3 and the other =4 and X is the angle between the hypothenuse and the side that =3. I'm supposed to find the sin, cos, tan, cot, sec, csc of X. I can't seem to get …
  3. math

    how would you create an equation for sec(2x) using both sec(x) and csc(x)?
  4. Pre Calculus.

    Can someone check my answers please!!! Simplify (tan ^2 theta csc^2 theta-1)/(tan^2 theta). My answer: 1 Simplify ((cos x)/(sec x-1)) + ((cos x) /(sec x +1) My answer: 2cot^2 x Find a numerical value of one trigonometric function of …
  5. Alg2/Trig

    Find the exact value of the trigonometric function given that sin u = 5/13 and cos v = -3/5. (Both u and v are in Quadrant II.) Find csc(u-v). First of all, I drew the triangles of u and v. Also, I know the formula of sin(u-v) is sin …
  6. Math (Precal)

    csc^2x secx/sec^2x+csc^2x simplify.
  7. pre cal

    can someone please show me how to verify this identity?
  8. Math/Trig

    Period: Asymptotes: Range: a) y= 2 sec (x) + 1 b) y= -2 csc (x - pi/2) c) y= 1 + tan (x + pi/4) d) y= 1/2 + csc (x - pi) + 1 e) y= cot (3x + pi) + 2 Any tips on drawing the graph?
  9. Trigonometry

    Simplify each expression using the fundamental identities. 1. Sec x csc x / sec^2x+csc^2x 2. Sec x + tan x / sec x + tan x - cos x
  10. Trig verifying identities

    I am having trouble with this problem. sec^2(pi/2-x)-1= cot ^2x I got : By cofunction identity sec(90 degrees - x) = csc x secx csc-1 = cot^2x Then split sec x and csc-1 into two fractions and multiplied both numerator and denominators …

More Similar Questions