physics
posted by Amy .
A 60.0kg skier with an initial speed of 12.0 m/s coasts up a 2.50mhigh rise and angle is 35 degrees.Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straightline path as shown in the figure.)

Wt. = Fg = m*g = 60kg * 9.8N/kg=588 N.=
Wt. of skier.
Fp=588*sin35 = 337 N.=Force parallel to
incline.
Fv = 588*cos35 = 482 N. = Force perpendicular to incline.
Fk = u*Fv = 0.08 * 482 = 38.5 N. = Force
of kinetic friction.
d =h/sinA = 2.5/sin35 = 4.36 m.
Ek + Ep = Ekmax  Fk*d
Ek = EkmaxEpFk*d
Ek=0.5*60*12^2588*2.538.5*4.36=2682 J.
Ek = 0.5m*V^2 = 2682 J.
30*V^2 = 2682
V^2 = 89.4
V = 9.5 m/s = Final velocity.
Respond to this Question
Similar Questions

Physics
a 61 kg skier on level snow coasts 184 m to stop from a speed on 12.0 m/s. A) use the work energy principle to find the coefficient of kinetic friction between the skis and the snow. B) suppose a 75 kg skier with twice the starting … 
Physics
A 61 kg skier on level snow coasts 184 m to stop from a speed of 12.0 m/s (A) use the work energy principle to find the coefficient of kinetic friction between the skis and the snow. B) suppose a 75 kg skier with twice the starting … 
Physics
A 61.8 kg skier coasts up a snowcovered hill that makes an angle of 26.0° with the horizontal. The initial speed of the skier is 6.10 m/s. After coasting a distance of 1.86 m up the slope, the speed of the skier is 4.48 m/s. Calculate … 
Physics 1
A 64.9 kg skier coasts up a snowcovered hill that makes an angle of 25.4° with the horizontal. The initial speed of the skier is 8.67 m/s. After coasting a distance of 1.92 m up the slope, the speed of the skier is 4.33 m/s. Calculate … 
physics
A 64.9 kg skier coasts up a snowcovered hill that makes an angle of 25.4° with the horizontal. The initial speed of the skier is 8.67 m/s. After coasting a distance of 1.92 m up the slope, the speed of the skier is 4.33 m/s. Calculate … 
physics
A 64.9 kg skier coasts up a snowcovered hill that makes an angle of 25.4° with the horizontal. The initial speed of the skier is 8.67 m/s. After coasting a distance of 1.92 m up the slope, the speed of the skier is 4.33 m/s. Calculate … 
physics
A 60 kg skier with an initial speed of 12 m/s coasts up a 2.5 m high rise that makes a 35 degree angle with the horizontal. If the coefficient of friction between the skis and the snow is .08, find the speed of the skier when he reaches … 
physics
A 64.2kg skier coasts up a snowcovered hill that makes an angle of 23.8° with the horizontal. The initial speed of the skier is 7.18 m/s. After coasting 1.96 m up the slope, the skier has a speed of 3.13 m/s. Calculate the work … 
Physics
A 65.0 kg skier with an initial speed of 11.0 m/s coasts up a 2.50 m high rise as shown in Figure 6.23. Find his final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. 
Physics
A 50.0 kg skier with an initial speed of 12.0 m/s coasts up a 2.50 m high rise as shown in Figure 6.23. Find his final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the …