algebra 2

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Which is the standard form of a circle with equation x^2 + 4x + y^2 - 6y = 3?

A. (x+2)^2+(y+9)^2=16

B. (x-2)^2+(y-9)^2=3

C. (x+2)^2+(y-3)^=16

D. (x+2)^2+(y-3)^2=3

  • algebra 2 -

    Nope. Forgot to add the constants to both sides of the equation.

    x^2 + 4x + y^2 - 6y = 3
    (x^2+4x+4) + (y^2-3y+9) = 3+4+9
    (x+2)^2 + (y-3)^2 = 16
    (C)

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