posted by Laarni .
Find the surface area and the lateral area of a regular square pyramid with base edge 6 and a lateral edge √34. PLEASE PLEASE HUHU Teach me how and what is lateral edge
lateral edge is an edge from the base to the vertex. As opposed to a base edge.
If the base edge is 6, the base diagonal is 6√2
Now draw a right triangle from the center of the base to the vertex, including one base corner.
(6√2/2)^2 + h^2 = (√34)^2
18 + h^2 = 34
h = 4
So, now we have height 4 and base edge 6, so the faces are triangles with
base = 6
height = √(3^2 + 4^2) = 5
lateral area is thus 4 * 1/2 (6)(5)
add the square base if desired.