AP Calc.
posted by Anon .
Simplify:
[(x^3)x]/[(x^2)1]

x^3x = x(x^21)

I don't get it...

sure you do. factor out x^21 top and bottom

but don't you have to get rid of the negative exponents somehow..?

sorry. I missed the negative exponents.
(x^3  x)/(x^(2)1)
(1  x^4)/x^3 / (1x^2)/x^2
(1x^4)/x^3 * x^2/(1x^2)
(1x^2)(1+x^2) / x(1x^2)
(1+x^2)/x 
How did you go from the original question to the 1st step?

1/x^3  x
over a common denominator of x^3, x = x^4/x^3 
ohmygosh.. i'm an idiot.. thank you! you're the bestt!(:
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