[(3/x)-(4/y)]/[(4/x)-(3/y)]
(4x-3y) / (3x-4y)
so?
I'm suppose to simplify it, but I keep getting 3y-4x/4y-3x. Can you please show me how to do it?!
They're the same!
Just multiply top and bottom by -1.
Algebra I, guy, algebra I.
Oops.. thankyou haha
To simplify the given expression, we can start by finding a common denominator for both fractions in the numerator and denominator. The least common denominator (LCD) for the fractions (3/x) and (4/y) is xy.
Let's rewrite the expression with a common denominator:
[(3/x)-(4/y)]/[(4/x)-(3/y)] --> [(3y/xy)-(4x/xy)] / [(4y/xy)-(3x/xy)]
Now, we can combine the fractions in the numerator and denominator:
[(3y-4x)/(xy)] / [(4y-3x)/(xy)]
Since we have the same denominator in both fractions, we can simplify further by multiplying the numerator by the reciprocal of the denominator:
[(3y-4x)/(xy)] * [(xy)/(4y-3x)]
Now, we can cancel out the common factors:
(3y-4x)/(4y-3x)
Thus, the simplified expression is (3y-4x)/(4y-3x).