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posted by C Wednesday, July 10, 2013 at 6:23pm.
Solve dy/dx for sin(xy)=1+x^3-y^2
sin(xy)=1+x^3-y^2 cos(xy) (y + xy') = 3x^2 - 2yy' y cos(xy) + xcos(xy) y' = 3x^2 - 2yy' (x cos(xy) + 2y) y' = 3x^2 - y cos(xy) y' = (3x^2 - y cos(xy)) / (x cos(xy) + 2y)
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