Calculus
posted by C
Solve dy/dx for sin(xy)=1+x^3y^2

Steve
sin(xy)=1+x^3y^2
cos(xy) (y + xy') = 3x^2  2yy'
y cos(xy) + xcos(xy) y' = 3x^2  2yy'
(x cos(xy) + 2y) y' = 3x^2  y cos(xy)
y' = (3x^2  y cos(xy)) / (x cos(xy) + 2y)
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