Post a New Question


posted by .

a crane drops a 1.0 kg steel ball onto a steel plate. the ball's speed just before impact is 2.0 m/s. if the average impact force is 300 N, and the ball is in contact with the plate for 0.01 seconds, what is the bounce back speed right after the impact.

  • physics -

    FΔt=Δp =p₂-(-p₁)=mv₁+mv₂
    (since p₁ directed ↓and p₂ ↑)
    v₂ = {FΔt- mv₁}/m =
    ={300•0.01 - 1•2}/1 = 1 m/s

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question