How much Tris-Acetate-EDTA (TAE) stock buffer (3.25 M) is required to make 400 ml of
solution that has a concentrations of 250 mM? How much water?
To calculate the amount of Tris-Acetate-EDTA (TAE) stock buffer (3.25 M) required to make 400 ml of solution with a concentration of 250 mM, we can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock buffer (3.25 M)
V1 = volume of the stock buffer to be used (unknown)
C2 = desired concentration of the final solution (250 mM)
V2 = final volume of the solution (400 ml)
Let's substitute the known values into the equation:
(3.25 M) * V1 = (250 mM) * (400 ml)
First, we need to convert the millimolar (mM) concentration to molar (M) by dividing by 1000:
(3.25 M) * V1 = (0.25 M) * (0.4 L)
Since the final volume is given in milliliters, we need to convert it to liters by dividing by 1000:
(3.25 M) * V1 = (0.25 M) * (0.4 L/1000)
Now, let's solve for V1:
V1 = (0.25 M) * (0.4 L/1000) / (3.25 M)
V1 ≈ 0.009846 L (rounded to 6 decimal places)
So, you would need approximately 0.009846 liters (or 9.846 ml) of the 3.25 M TAE stock buffer to make 400 ml of solution with a concentration of 250 mM.
To calculate the amount of water required, we subtract the volume of the stock buffer from the total volume:
Volume of water = Volume of solution - Volume of stock buffer
Volume of water = 400 ml - 9.846 ml
Volume of water ≈ 390.154 ml (rounded to 3 decimal places)
Therefore, you would need approximately 390.154 ml of water for the remaining volume in the solution.