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The distribution of heights of adult American men is approximately normal with a mean of 68 inches and a standard deviation of 2 inches. What percent of mean are at least 72 inches tall?

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  • math -

    z = (x -mean)/ sd

    z = (72-68)/2
    z= 4/2= 2

    1-.9772 = .0228

    2.28%

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