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A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at 22 °C, assuming volume remains constant?

  • chemistry -

    Assuming the gas is ideal, we use Gay-Lussac's Law to relate the relationship between Temperature & Pressure of gas:
    P1/T1 = P2/T2
    T1 = initial temperature of gas (in K)
    T2 = final temperature of gas (in K)
    P1 = initial pressure of gas
    P2 = final pressure of gas
    *note that to convert Celsius to Kelvin, we just add 273.
    (0.370)/(50+273) = P2/(22+273)
    P2 = (0.370)(323)/295
    P2 = ?

    now solve for P2. units in atm.
    hope this helps~ :)

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