Physics
posted by Danny
A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced.
ANS 1 = kPa (3 decimal places)
ANS 2 = (6 decimal places)
1.000cm = 0.01m
2.900cm = 0.029m
length = 1m
Bar extension = 1.500mm = 0.0015m
Area = w * h
= 0.01 * 0.029
= 0.00029
Stress = Load/ Area
= 189000.000N/ 0.000290
= 651724137.9Pa
ANS = 651724.1379kPa
Strain = 0.0015/ 8.7
= 1.7241 * 10^4
ANS = 0.000172
Please check. Thank you.
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