econ 112

posted by .

A random sample of 400 morning shoppers showed that 130 were men. A random sample of 480 evening shoppers showed 187 to be men. Use a 5% level of significance to test for a significant difference in the proportion of morning and evening male shoppers. What is your conclusion?

  • econ 112 -

    n1= 400
    x1 = 130
    n2 = 480
    x1 = 187

    phat1 = x1/n1 = 130/400 = .325

    phat2 = x2/n2 = 187/480 = .3896

    pbar = (x1 + x2)/(n1+n2) = (130 +187)/(400+480) = .36
    qbar = 1- pbar = .64

    z = (325- .3896)/sqrt(.36*.64/400+ .36*.64/480)

    z = -1.99
    If p-value greater than alpha
    Fail to reject Ho
    If p-value less than alpha
    Reject Ho

    p-value = 0.047

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. statistics

    3 In 1999, a sample of 200 in-store shoppers showed that 42 paid by debit card. In 2004, a sample of the same size showed that 62 paid by debit card. (a) Formulate appropriate hypotheses to test whether the percentage of debit card …
  2. Statistics

    A recent study was designed to compare smoking habits of young women with those of young men. A random sample of 150 women revealed that 45 smoked. A random sample of 100 men indicated that 25 smoked. At the 0.05 significance level …
  3. statistics

    According to a Louis Harris poll, 63% of men drivers always use seat belts. A recent sample of 900 men drivers showed that 60% of them always use seat belts. Test at the 1% significance level if the proportion of men drivers who always …
  4. statistics

    A random sample of 80 youths and a second random sample of 120 adults showed that 18 of the youths and 10 of the adults had been ticketed for careless driving. Use a 1% level of significance to test the claim that youth have a higher …
  5. statistics

    A random sample of 84 shoppers were interviewed and 51 said they prefer to shop alone rather than with someone such as friends or family. Let p represent the proportion of all shoppers at this mall who would prefer to shop alone. Find …
  6. Statistics

    2. In 2009 a random sample of 70 unemployed people in Alabama showed an average weekly benefit of $199.65. In Mississippi, for a random sample of 65 the number was $187.93. Assume population standard deviations of $32.48 and $26.15 …
  7. Econ 112

    A researcher believes that the average size of farms in the U.S. has increased from the 2002 mean of 471 acres. She took a sample of 23 farms in 2011 to test her belief and found a sample mean of 498.8 acres and a sample standard deviation …
  8. STAT

    A college faculty consists of 400 men and 250 women. The college administration wants to draw a sample of 65 faculty members to ask their opinion about a new parking fee. They draw a simple random sample of 40 men and another simple …
  9. STAT

    The mean weight of all 20-year old women is 130 pounds. A random sample of 30 women athletes who are 20 years old showed a sample mean of 126 pounds with a standard deviation of 15 pounds. Researchers wanted to determine whether the …
  10. Math

    Managers of a local shopping mall selected a random sample of shoppers and recorded the gender of each. Here are their results. Gender Number of People Male 69 Female 106 Based on this sample, how many of the next 2000 shoppers would …

More Similar Questions