Math (Quadratics)(Discriminants)
posted by Drake .
If a is a real number and a cubic equation
f(x)=x^3−8x^2+(a+12)x−2a
has a repeated root, what is the sum of all the possible values of a?

The repeated root cannot be complex, nor can the other.
If f(x) = (xh)^2 (xk) then
x^3  (2h+k)x^2 + (2hk+h^2)x  kh^2 = x^38x^2+(a+12)x2a
so
2h+k = 8
h(2k+h) = a+12
kh^2 = 2a
k = 82h
h(163h) = a+12
h^2(4h) = a
h(163h) = h^2(4h) + 12
h^3  7h^2 + 16h  12 = 0
(h2)^2 (h3) = 0
So,
h = 2 or 3
k = 4 or 2
a = 8 or 9