# How do I solve for this??

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How much heat (in Joules) is gained by the water when a chemical reaction takes place in 100.0 ml aqueous solution, has a temperature increase of 12.67°C and a specific heat capacity of 4.180 J/°Cg? [Hint: ignore any effects of the calorimeter and solve for qwater]

• How do I solve for this?? -

H (joules)
=ΔT*m*Q
where
H=energy required (joules)
ΔT=change in temperature (°C)
m=mass (g)
Q=specific heat in j/°C/g

So
heat gain
=12.67 °C * 100 g * 4.180 j/°C/g
=5296 j

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