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What will be the final volume of a 425 mL sample of gas initially at 22 degrees C and 1 atm pressure when the temperature is changed to 30 degrees C and the pressure to 0.471 atm?

  • chem -

    PV = kT
    V = kT/P
    Given new P and T, call them P' and T', we have

    V' = kT'/P'

    V'/V = kT'/P' * P/kT = (T'/T)(P/P')

    P' = .471P
    T' = (30+273)/(22+273) = 1.0271T

    So, we now must have

    V'/V = 1.0271/.471 = 2.18
    V' = 2.18 * 425 = 927 mL

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