A saturated solution of barium chloride at 30 degrees celcius contains 150g of water. How much additional barium chloride can be dissolved by heating this solution by heating this solution to 60 degrees.

Solubility of Bacl @ 30 degrees=38.2g/100g water
solubility of Bacl @ 60 degrees =46.6g/100g water

How is this problem solved?

I worked that for you below. Go back and look at your posts before you post again.

To solve this problem, you need to calculate the amount of barium chloride that can be dissolved in the additional water when the temperature is increased from 30 degrees Celsius to 60 degrees Celsius.

First, you need to find out how much barium chloride is already dissolved in the saturated solution at 30 degrees Celsius. The problem states that the solution contains 150 grams of water. Since the solubility of barium chloride at 30 degrees Celsius is 38.2 grams per 100 grams of water, you can calculate the amount of barium chloride dissolved using the following equation:

Amount of barium chloride dissolved = (solubility of BaCl @ 30 degrees / 100) * mass of water

Plugging in the values, we have:

Amount of barium chloride dissolved = (38.2 / 100) * 150 = 57.3 grams

So, initially, there are already 57.3 grams of barium chloride dissolved in the solution.

Next, you need to determine the additional amount of barium chloride that can be dissolved when the temperature is increased to 60 degrees Celsius. The problem states that the solubility of barium chloride at this temperature is 46.6 grams per 100 grams of water.

Using the same formula as before, we can calculate the additional amount of barium chloride that can be dissolved:

Additional amount of barium chloride dissolved = (solubility of BaCl @ 60 degrees / 100) * mass of additional water

The mass of additional water can be calculated by subtracting the initial mass of water (150 grams) from the final mass of water at 60 degrees Celsius.

Plugging in the values, we have:

Additional amount of barium chloride dissolved = (46.6 / 100) * (final mass of water - 150)

The final mass of water at 60 degrees Celsius is not provided in the question, so you would need to have that information to calculate the amount of additional barium chloride that can be dissolved.

Once you have the final mass of water, you can substitute it into the equation and solve for the additional amount of barium chloride dissolved.