math check
posted by Tom 12 .
Consider the following table and use the formulas that are given for computing the correlation coefficient. (Give your answer correct to two decimal places.)
x 1 1 0 0 0
y 7 3 5 6 6
r =
n
xy
−
x
y
n
x2
−
x
2
n
y2
−
y
2
(1)
r =
SS(xy)
SS(x) ยท SS(y)
(2)
This is what I done (2)(27)/5 =10.8 for ss(xy) then 2^/5=.8 for SS(x), ten (27^)/5=145.8 for SS(y), then I put 10.8 over sqrt.8 X 145.8 = 1.00
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