# Math for Educators

posted by .

I am thinking of some #s less than 100. When I divide them by 2 there is a remainder of 1. When I divide them by 3 there is a remainder of 1. When I divide it by 4 there is a remainder of 1. However, when I divide by 5 there is no remainder. what are the #'s?

- my answer so far is every number ending in a zero or five from 1-100 but I don't think its that simple. If someone could help me figure this out it would be greatly appreciated!

• Math for Educators -

The statement, "when I divide them by 2, there is a remainder of 1" means that the numbers must be odd, therefore they can't end in a 0. I'm only seeing 2 answers, 25 and 85

• Math for Educators -

like Joe said, the first condition limits you to odd numbers
the second condition limits you to the numbers
7 13 19 25 31 37 43 49 55 61 67 73 79 85 91 97 (every odd multiple of 3 + 1)
the third condition limit you to the numbers
5 9 13 1721 25 29 33 37 41 45 49 53 57 61 65 69 73 77 81 85 89 93 97 ( every multiple of 4 + 1)
the fourth conditon gives you
5 15 25 35 45 55 65 75 85 95

As Joe pointed out , the only numbers fitting all 4 conditions are
25 and 85

## Similar Questions

1. ### Algebra 2

I know it's easy, but I totally just blanked out on how to divide rational expressions. We're supposed to write them in the form quotient + (remainder/Divisor) For example, (2h2+h-2)/(h2-1) Those are h squareds. I know you would take …
2. ### algebra

Divide (3x^3-x^2+8x-9) by (x-1) Please help! I'll show you how this works out: 3x^2 + 2x + 10 x - 1 | 3x^3 - x^2 + 8x - 9 3x^3 - 3x^2 2x^2 + 8x 2x^2 - 2x 10x - 9 10x - 10 1 Remember when you subtract, you change the signs. This did …
3. ### math proportions

The remainder is a fraction (remainder/divisor). Why don't you use a calculator...for instance, 31/7 is 4 r 3, but it is easy enought to just put 31 divide by 7 in the calc. I have to solve a proportion, and the answer I come up with …
4. ### math

what is the least common positive integer that meets the following conditions: divided by 7 with remainder 4 divided by 8 with remainder 5 divided by 9 with remainder 6 i thought you could add 7 and 4 to get 13, then divide 13 and …
5. ### math

what is the least common positive integer that meets the following conditions: divided by 7 with remainder 4 divided by 8 with remainder 5 divided by 9 with remainder 6 i thought you could add 7 and 4 to get 13, then divide 13 and …
6. ### Algebra

(4x^3-9x+8x^2-18)/(x+2)-use synthetic division to divide. I set it up like this (pretend the parentheses are the synthetic division box). (-2) 4 8 -27 4 0 -27. For remainders, according to my book, we're supposed to divide the remainder …
7. ### math

find all numbers that divide 100 with a remainder of 4. what is the largest 2-digit divisor that can divide 100 and still have a remainder of 4?