PLEASE HELP !!!
A mason is putting in the foundation for a wall. His assistant digs a trench in roughly the shape of a rectangular solid measuring 50 ft. in length, 12 inches deep along both sides, and 12 inches wide at the top and bottom. How many cubic feet of earth did he remove (to the nearest tenth)?
V = LWH
V = 50 * 1 * 1
V=LWH
V=50*12*12
V=7200
IS THAT CORRECT
No. Jaleah, that's wrong. You're given feet and inches. You nee dto convert inches to feet.
To find the volume of the earth that was removed, you need to calculate the volume of the rectangular solid-shaped trench.
To do this, you can use the formula for the volume of a rectangular solid, which is length x width x height.
In this case:
- The length of the trench is given as 50 ft.
- The depth (height) of the trench is given as 12 inches. To calculate the volume in the same units, you need to convert the depth to feet. Since there are 12 inches in a foot, divide the depth by 12: 12 inches / 12 inches/foot = 1 foot.
- The width of the trench at the top and bottom is given as 12 inches. Again, you need to convert this to feet. Similarly, divide the width by 12: 12 inches / 12 inches/foot = 1 foot.
Now, you can calculate the volume of the trench by multiplying these values: 50 ft x 1 ft x 1 ft = 50 cubic feet.
Therefore, the assistant removed approximately 50 cubic feet of earth.