Zn(s) + 2AgNO3(aq) = 2Ag(s) + Zn(NO3)2 (aq)
It would require_____g of zinc to produce 5.40g of silver.
1.64
To determine the amount of zinc required to produce 5.40g of silver, we need to use the balanced chemical equation. The balanced equation is:
Zn(s) + 2AgNO3(aq) -> 2Ag(s) + Zn(NO3)2(aq)
From the equation, we can see that the ratio of zinc (Zn) to silver (Ag) is 1:2. This means that for every 1 mole of silver produced, we need 1 mole of zinc.
To calculate the amount of zinc required, we can use the molar mass of silver (Ag) and the molar mass of zinc (Zn). The molar mass of Ag is 107.87 g/mol, and the molar mass of Zn is 65.38 g/mol.
1. Convert the given mass of silver (5.40g) to moles:
moles of Ag = mass / molar mass = 5.40g / 107.87 g/mol = 0.050 mol
2. According to the stoichiometry of the balanced equation, the ratio of Zn to Ag is 1:2. Therefore, the moles of Zn required will be half of the moles of Ag:
moles of Zn = moles of Ag / 2 = 0.050 mol / 2 = 0.025 mol
3. Finally, we can calculate the mass of zinc required:
mass of Zn = moles of Zn × molar mass of Zn = 0.025 mol × 65.38 g/mol = 1.6345 g
Therefore, it would require approximately 1.6345 grams of zinc to produce 5.40 grams of silver.
To determine the amount of zinc required to produce 5.40g of silver, we need to use stoichiometry.
First, let's establish the balanced chemical equation:
Zn(s) + 2AgNO3(aq) → 2Ag(s) + Zn(NO3)2(aq)
From the equation, we can see that the molar ratio between zinc (Zn) and silver (Ag) is 1:2.
Now, we need to calculate the molar mass of silver (Ag) and zinc (Zn):
- Molar mass of Ag: 107.87 g/mol
- Molar mass of Zn: 65.38 g/mol
To find the number of moles of silver produced, we can use the formula:
Number of moles = Mass / Molar mass
Number of moles of Ag = 5.40 g / 107.87 g/mol = 0.050 mol (rounded to three decimal places)
Since the molar ratio of Ag to Zn is 2:1, we can infer that the number of moles of zinc required is half of the number of moles of silver:
Number of moles of Zn = 0.050 mol / 2 = 0.025 mol (rounded to three decimal places)
Finally, to calculate the mass of zinc required, we can use the formula:
Mass = Number of moles * Molar mass
Mass of Zn = 0.025 mol * 65.38 g/mol ≈ 1.63 g (rounded to two decimal places)
Therefore, it would require approximately 1.63 g of zinc to produce 5.40 g of silver.
ensure the equation is balanced.
obtain the mole ratio between Zn and Ag i.e. 1 mole of Zn produces 2 moles of Ag
convert the mass of Ag (m=5.4g) into mole using m/Mr where Mr is the molar mass of Ag.
take note of that mole for Ag and use it to calculate the mole for Zn, using the mole ratio.
then convert the mole for Zn to mass using the same formula m/Mr to get your required mass of Zn.