maths
posted by Anonymous .
How many ordered triples of pairwise distinct, positive integers (a,b,c) are there such that abc=10^6?

10^6 = (2x5)^6
= (2^6)(5^6)
Possible cases:
1x64x15628  arrange in 6 ways
2x32x15625  arrange in 6 ways
4x16x15625  6 more
8x8x15625  arrange in 3 ways
64x5x3125  6 ways
64x25x625  6 ways
64x125x125  3 ways
I count 36 of them
check my logic to make sure I didn't miss any
e.g. for 64x25x625 we could have
(64,25,625) , (64,625,25) , (25,64,625), (25,625,64), (625,25,64), (625,64,25) 
false

Do ur hw ur self .....
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