# Physics

posted by
**Danny**
.

1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters.

A) What is the acceleration? = m/s^2

B) What is its speed after deceleration? = km/h

Initial velocity (u) = 110km/h

Time (t) = 20s

Distance = 450m

Using this formula s = ut + 1/2 at^2

I need some help. Thank you.