Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds then together they would weigh 250 pounds. How much does each of them weigh? let x be ken's weight.
my work: 2x - 30 = j
x+ 10 + J = 250
and now im stuck, can someone show me how to find their weight and solve these equations cause im confused, thanks :)
combine your equations:
x+10+2x-30=250
then
3x-20=250
then
3x=270
then
x=90
Ken weighs 90 and Joe weighs 150
well, since x+10+j = 250
x = 240-j
plug that into the other equation and you have
2(240-j) - 30 = j
480 - 2j - 30 = j
450 = 3j
j = 150
so, x = 240-150 = 90
Thank you so much :)
To solve the system of equations, you can use the method of substitution. Let's start solving step by step:
1. Create the equations based on the given information:
- Joe weighs 30 lbs less than twice Ken's weight: J = 2x - 30
- If Ken gains 10 pounds, then together they would weigh 250 pounds: Ken's weight + Joe's weight = 250, substitute J with 2x - 30: x + (2x - 30) = 250
2. Simplify the equation by combining like terms:
3x - 30 = 250
3. Move the constant term to the other side of the equation:
3x = 280
4. Solve for x by dividing both sides of the equation by 3:
x = 280 / 3
x ≈ 93.33
Now that we have found Ken's weight (x ≈ 93.33), we can substitute this value back into the equation for Joe's weight (J = 2x - 30) to find Joe's weight:
J = 2(93.33) - 30
J ≈ 156.67
Therefore, Ken weighs approximately 93.33 pounds, while Joe weighs approximately 156.67 pounds.