Statistics

posted by .

women's heights are normally distributed with a mean 63.1 in and standard deviation of 2.5. A social organization for tall people has a requirement that women must be at least 69in tall. What percentage of woman meet that requirement?

The percentage of woman that are taller than 69in is __%

  • Statistics -

    z = (69-63.1)/ 2.5
    z = 5.9/2.5
    z = 2.36

  • Statistics -

    z = (69-63.1)/ 2.5
    z = 5.9/2.5
    z = 2.36

    Once you have z-scores, check a z-table for the probability scores. Convert to a percentage.

  • Statistics -

    erg

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. statistics

    Women’s heights are normally distributed with a mean of 63.6 in and a sd of 2 .5in. The US Army requires women’s heights to be between 58 in and 80 in. Find the percentage of women meeting that height requirement.
  2. Statistics

    Assume the heights of women are normally distributed with a mean given by 63.6 inches and a standard deviation given by 2.5 inches, the US Army requires women's height to be between 58 and 80 inches. Find the percentage of women meeting …
  3. statistics

    The heights of American women aged 18 to 24 are normally distributed with a mean of 66 inches and a standard deviation of 2.5 inches. In order to serve in the U.S. Army, women must be between 57 inches and 79 inches tall. What percentage …
  4. statistics

    The heights of American women aged 18 to 24 are normally distributed with a mean of 66 inches and a standard deviation of 2.5 inches. In order to serve in the U.S. Army, women must be between 57 inches and 79 inches tall. What percentage …
  5. statistics

    you have requirement that men must be at least 74 in tall and women must be at least 70 in tall. the men height is 69 in +/-2.8 and women mean height is 63.6 +/-2.5. If the requirement s changed so that the tallest 4% of men and women …
  6. statistics

    Assume that women's heights are normally distributed with a mean=63.6 in. and standard deviation = 2.5 in. a) To be eligible for the US Marine Corps, a woman must have a height between 58 in. and 73 in. Find the percentage of women …
  7. statistics

    Tall clubs international is a social organization for tall people. It has a height requirement that men must be at least 74 in. and women must be at least 70 in. tall. If men's heights have a normal mean of 69.0 in and a deviation …
  8. Statustics

    A survey found that women’s heights are normally distributed with mean 63.4 in and standard deviation 2.5 in. A branch of the military requires women’s heights to be between 58 in and 80 in. a. Find the percentage of women meeting …
  9. statistics

    A survey found that women's heights are normally distributed with mean 62.4 in and standard deviation 2.8 in. The survey also found that men's heights are normally distributed with a mean of 68.9 in. and standard deviation 2.8. Complete …
  10. statistic

    A survey found that​ women's heights are normally distributed with mean 62.5 in. and standard deviation 2.7 in. The survey also found that​ men's heights are normally distributed with a mean 67.9 in. and standard deviation …

More Similar Questions