# algebra

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The question I have is to solve the problem.
A model rocket is launched from the ground with an initial speed of 50 feet per second. The equation that models its height, h feet, off the ground t seconds after it was fired is
h=-16ft^2+50t
a)How high is the rocket 1 seconds after it was fired?

• algebra -

a. h = 50*1 - 16*1^2 = 34 Ft.

b. V = Vo + g*t
Tr = (V-Vo)/g = (0-50)/-32 = 1.56 s. =
Rise time.
Tf = Tr = 1.56 s. = Fall time.

T = Tr + Tf = 1.56 + 1.56 = 3.125 s. =

t

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