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posted by Mat Tuesday, May 21, 2013 at 9:38am.
Find the area of the region between the parabola 4y = x^2 and the line 3x + 4 y = 4
The curves intersect at (-4,4) and (1,1/4) So, just integrate to find a = ∫[-4,1] (4-3x)/4 - x^2/4 dx a = 125/24
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