If 50 mL of a saturated solution of KClO3 at 55¡ÆC is cooled to 15¡ÆC, calculate the mass of precipitate that will form
I can't decipher the funny symbols and you don't tell us the solubility of KClO3 at the two tempeatures.
To calculate the mass of precipitate that will form when a saturated solution of KClO3 is cooled, we need to use the concept of solubility.
1. First, we need to determine the solubility of KClO3 at the given temperatures of 55¡ÆC and 15¡ÆC. The solubility of a substance usually changes with temperature.
2. Once we have the solubility values, we can determine if the solution is saturated or not. If the concentration of KClO3 in the solution at 55¡ÆC exceeds its solubility at that temperature, then the solution is saturated.
3. We also need to know if KClO3 is a soluble or insoluble compound. If it is soluble, it will not form a precipitate regardless of the temperature change.
4. If KClO3 is insoluble, we can assume that a precipitate will form when the temperature of the solution is decreased from 55¡ÆC to 15¡ÆC. In this case, the solubility of KClO3 at 15¡ÆC will determine the maximum mass of the precipitate that can form.
5. To calculate the mass of the precipitate, we would subtract the final concentration of KClO3 in the cooled solution from its initial concentration at 55¡ÆC. Then, we multiply this concentration difference by the volume of the solution that underwent the temperature change (50 mL) to obtain the mass of the precipitate.
Therefore, to accurately calculate the mass of precipitate that will form, we need to know the solubility of KClO3 at 55¡ÆC and 15¡ÆC, and whether KClO3 is a soluble or insoluble compound.