math calculus (please help me)
posted by steven
Solve for t. (Round your answer to two decimal places.
(2 − (2.479/35))^7t= 29

Reiny
take log of both sides
log [(2 − (2.479/35))^7t= 29] = log 29
7t log(2 − (2.479/35)) = log 29
7t(.2853...) = log 29
7t = log 29/.2853... = 5.1245...
t = .732078
= appr .73
check:
using 2 decimals
(2 − (2.479/35))^7t= 29.00000003 , not bad
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