If the electrical field due to a point charge is .000602N/C what is the magnitude of the field (N/C)3.51 times as far away?
To find the magnitude of the electric field 3.51 times as far away from a point charge, we can use the inverse square law for electric fields.
The inverse square law states that the magnitude of an electric field is inversely proportional to the square of the distance from the point charge.
Let's call the initial distance from the point charge as r1, and the final distance as r2. According to the question, r2 is 3.51 times r1.
So, we can set up the equation:
E1 / E2 = (r2 / r1)^2
Where E1 is the magnitude of the electric field at distance r1, and E2 is the magnitude of the electric field at distance r2.
Plugging in the values we have:
E1 = 0.000602 N/C
r2 = 3.51 * r1
Now we can solve for E2:
E1 / E2 = (r2 / r1)^2
0.000602 N/C / E2 = (3.51 * r1 / r1)^2
0.000602 N/C / E2 = (3.51)^2
To find E2, we can rearrange the equation:
E2 = 0.000602 N/C / (3.51)^2
Calculating the answer:
E2 = 0.000602 N/C / 12.3201
E2 ≈ 0.0000489 N/C
So, the magnitude of the electric field 3.51 times as far away is approximately 0.0000489 N/C.