College Algebra HELP
posted by Rosie .
Use the seven step method described in the book to graph the following rational function
f(x)=(2x^2+x3)/(2x^27x)
1) Determine the symmetry of the function
2) Find the yintercept
3) Find the xintercept
4) Find the vertical asymptotes
5) Find the horizontal asymptotes
6) Plot points between and beyond the xintercept and the vertical asymptotes.
Type the ycoordinate for each of the following points:
5 2 1 2 5
7) What should the graph look like

f(x) = (2x+3)(x1) / x(2x7)
So, the denominator is zero at x=0,7/2 making vertical asymptotes
Top and bottom are both quadratics with x^2 coefficient=2, so there is a horizontal asymptote at y = 2/2 = 1
There is no yintercept, because f(x) is not defined for x=0
It's easy to see where y=0
f(x) is neither even nor odd, so there is no symmetry
visit wolframalpha.com to check out the graph. Just type in the function
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