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Three identical conducting spheres are located at the vertices of an equilateral triangle ABC. Initially the charge the charge of the sphere at point A is q A =0 and the spheres at B and C carry the same charge q A =q B =q. It is known that the sphere B exerts an electrostatic force on C which has a magnitude F=4N. Suppose an engineer connects a very thin conducting wire between spheres A and B. Then she removes the wire and connects it between spheres A and C. After these operations, what is the magnitude of the force of interaction in Newtons between B and C?

  • physics -

    F(BC) =kq²/a².

    q´(B)=q´(A) =(q+0)/2=q/2,
    q´´(A) =q´(C) = {q´(A)+c(C)}/2 = 3q/4,

    F´(BC) =k q´(B)• q´(C)/a² =
    =(3/8)• kq²/ a²=3•4/8=3.2 = 1.5 N

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