Chemistry

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2.76 grams of silver carbonate produced a 50 percent yield of silver oxide. what is the actual mass of this reaction

  • Chemistry -

    g Ag2O = g Ag2CO3 x (molar mass Ag2O/molar masss Ag2CO3) = ? at 100% yield.
    That times 0.50 = g Ag2O actually produced.

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