Physics
posted by birju .
Temperature of a diatomic gas is 300k. If the moment of inertia of its molecules is 8.28*10^38 gmcm^2. Calculate their root mean square angular velocity.

Please give the complete solution

I=8.28•10⁻³⁸ g•cm²=8.28•10⁻⁴⁵kg•m²,
I=2mr²/3 =>
radius of diatomic molecule
r=sqrt{3•I/2m}
Root mean square speed v =sqrt{3kT/m}.
v = ωr.
Angular root mean square speed
ω=v/r= =sqrt{2kT/I} =
=sqrt{2•1.38•10⁻²³•300/8.28•10⁻⁴⁵}=
=1•10¹² rad/s 
Thanks, Elena...