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physics

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A uniform 5.9 T magnetic field points north.
If an electron moves vertically downward (toward the ground) with a speed of 0.85 × 107
m/s through this field.
The charge on a proton is 1.60×10−19
.
a) What is the magnitude of the force acting
on it?
Answer in units of N

  • physics -

    F=qvBsinα
    sinα = sin180= 0 => F=0

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