geometry
posted by JoAnne .
The construction of the regular pentagon is equivalent to the construction of the point in the unit circle with x coordinate x1 = the square root of 5  1 divided by 4. Use this to construct a regular pentagon that has all its vertices inside the unit circle. Write a construction protocol and justify all your construction steps. How do I construct the square root of 51?

You must mean
√5  1
draw a square ABCD with sides 2 , where A and B are the endpoints of the base
Extend the length of the base to the right
Draw a vertical MN where M is the midpoint of AB and N is the midpoint of CD
You should see a rightangled triangle with legs AB = 1 and MN = 2
by Pythagoras AN = √5
Use your compass, centre at A and radius AN , draw an arc to cut the entension of AB at P
so AP = √5
and MP = √5  1