Post a New Question

physics

posted by .

an object is thrown upward with an initial velocity 'u' m/s. derive an expression for the height 'h' at which its kinetic energy becomes equal to its potential energy.

  • physics -

    h=(u²- v²)/2g
    v²=u²- 2gh,
    KE=m•v²/2= m(u²- 2gh)/2,
    KE=PE =>
    m(u²- 2gh)/2 =mgh,
    (u²- 2gh)/2= gh,
    u²=4gh,
    h= u²/4g.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question