calc
posted by Anonymous .
integrate 1/(1+(e^x))
please provide steps

1/(1+(e^x))
= 1/(1 + 1/e^x)
= 1/( (e^x + 1)/e^x )
= e^x/(e^x + 1)
now by "recognition" of how to differentiate Ln(anything) = anything'/anything
I get
∫1/(1+(e^x)) dx
= ln(e^x + 1) + c
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