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integrate 1/(1+(e^-x))

please provide steps

  • calc -

    = 1/(1 + 1/e^x)
    = 1/( (e^x + 1)/e^x )
    = e^x/(e^x + 1)

    now by "recognition" of how to differentiate Ln(anything) = anything'/anything
    I get
    ∫1/(1+(e^-x)) dx
    = ln(e^x + 1) + c

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