Physics

posted by .

A circuit contains a self-inductance L in series with a capacitor C and a resistor R. This circuit is driven by an alternating voltage V=V0sin(ωt). We have L=0.015 H, R= 80 Ω, C= 5e-06 F, and V0=40 volts.

(a) What is the value (in radians/seconds) of the resonance frequency, ω0?

(b) Consider three separate cases for which ω= 0.25 ω0, ω=ω0, and ω= 4 ω0 respectively. For each case calculate the the peak current I0 in Amperes.

ω= 0.25 ω0: ?
ω= 1 ω0: ?
ω= 4 ω0: ?

(c) Find the energy UC(t) and the energy UL(t) stored in the capacitor and in the inductor, respectively, at time t1=0.0003 seconds for ω=ω0. Express your answers in Joules.

UC(t1): ??
UL(t1):

  • Physics -

    a. Wo^2=1/LC=1/(0.015*5*10^-6)=1.33*10^7
    Wo = 3651 Rad/s.

    b. Xl=0.25Wo*L=0.25*3651*0.015=13.7 Ohm
    Xc=1/(0.25*3651*5*10^-6) = 219 Ohms.
    Z^2 = R^2 + (Xl-Xc)^2
    Z^2 = (80)^2 + (13.7-219)^2 = 48,548.1
    Z = 220.3 Ohms.
    Im = V/Z = 40/220.3 = 0.182A.

    Xl = W*L = 3651*0.015 = 54.77 Ohms
    Xc = 1/W*C=1/(3651*5*10^-6)=54.77 Ohms.
    Z^2 = R^2 + (Xl-Xc)^2
    Z^2 = 80^2 + (54.77-54.77)^2=6400
    Z = 80 Ohms.
    Im = V/R = 40/80 = 0.5A.

    Xl = 4Wo*L = 4*3651*0.015 = 219.1 Ohms.
    Xc=1/4Wo*C=1/(4*3651*5*10^-6)=13.7 Ohms
    Z^2 = 80^2 + (219.1-13.7)^2 = 48,589.2
    Z = 220.3.
    Im = V/Z = 40/220.3 = 0.182A.

  • Physics -

    thnx henry !

    plz last part is remaining nw....
    (c) Find the energy UC(t) and the energy UL(t) stored in the capacitor and in the inductor, respectively, at time t1=0.0003 seconds for ω=ω0. Express your answers in Joules.

    UC(t1): ??
    UL(t1):

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    An R-C circuit is driven by an alternating voltage of amplitude 110 and frequency . Define to be the amplitude of the voltage across the capacitor. The resistance of the resistor is 1000 , and the capacitance of the capacitor is 1.00 …
  2. Physics

    An R-C circuit is driven by an alternating voltage of amplitude 110 V and frequency w. Define V0 to be amplitude of the voltage across the resistor. The resistance of the resistor is 1000 ohms and the capacitance of the capacitor is …
  3. physics

    In a series circuit, a generator (1254 Hz, 13.8 V) is connected to a 15.5-Ω resistor, a 4.25-µF capacitor, and a 5.32-mH inductor. Find the voltage across each circuit element. VR = VC = VL =
  4. Circuits

    I have to calculate the voltage across the resistor of an rlc circuit where the 4.7nF capacitor is in parallel with the .200 H inductor for different frequencies (starting with 1000 Hz) They appear at the top of the circuit and they …
  5. Doogleberry Physcis

    In an L-R-C series circuit, the resistance is 380 Ohms, the inductance is 0.400 H, and the capacitance is 2.00×10−2 uF. What is the resonant frequency of the circuit?
  6. Physics

    A circuit contains a self-inductance L in series with a capacitor C and a resistor R. This circuit is driven by an alternating voltage V=V0sin(ωt). We have L=0.015 H, R= 80 Ω, C= 5e-06 F, and V0=40 volts. Q) Find the energy …
  7. Physics 112

    A battery is connected in series with a R = 0.26 Ω resistor and an inductor, as shown in the figure below. The switch is closed at t = 0. The time constant of the circuit is τ = 0.10 s, and the maximum current in the circuit …
  8. physics

    A series RLC circuit is made with a C=100pF capacitor, an L=100μH inductor, and an R=30Ω resistor. The circuit is driven at 5×106rad/s with a 1V amplitude. What is the current oscillation amplitude in amps
  9. physics

    A series RLC circuit is made with a C=100pF capacitor, an L=100μH inductor, and an R=30Ω resistor. The circuit is driven at 5×106rad/s with a 1V amplitude. What is the current oscillation amplitude in amps
  10. Physics

    A 10.0 Ω resistor is hooked up in series with an 8.0 Ω resistor followed by a 27.0 Ω resistor. The circuit is powered by a 9.0 V battery -Calculate the equivalent resistance. -Calculate the voltage drop across each resistor …

More Similar Questions