Chemistry

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For a solution of 3.3 M H2CO3 (Ka = 4.4 × 10-7), calculate:


(a) [H+] ____?______M

(b) pH _____??______

(c) percent ionization ______?______%

  • Chemistry -

    I don't think it wise to write the Ka for H2cO3 as 4.4E-7 because it has TWO ionization constants. It is correct to write k1 = 4.4E-7.
    ...........H2CO3 ==> H^+ + HCO3^-
    I.........3.3M.......0.......0
    C.........-x.........x.......x
    E.........3.3-x.......x......x

    k1 = 4.4E-7 = (H^+)(HCO3^-)/(H2CO3)
    Substitute into k1 exprsession and solve for x = (H^+) and convert that to pH.
    % ion = [(H^+)/(H2CO3)]*100 = ?

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