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Calculus 1  implicit differentiation
I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4. I would appreciate any help that can be offered. 
Calculus 1  implicit differentiation
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Find y" by implicit differentiation. x^3+y^3 = 1 (x^3)'+(y^3)' = (1)' 3x^2+3y^2(y') = 0 3y^2(y') = 3x^2 y' = 3x^2/3y^2 y' = x^2/y^2 y" = [(y^2)(x^2)'(x^2)(y^2)']/y^4 y" = [(y^2)(2x)(x^2)(2y)]/y^4 y" = [(2xy^2)(2yx^2)]/y^4 …