Chemistry
posted by Emily .
A sample of argon gas at STP occupies 56.2 liters. Find the number of moles of argon and the mass in the sample

1 mol occupies 22.4 L at STP. Solve for n, then n = grams/molar mass. You know molar mass and n, solve for grams.
OR you may use PV = nRT to solve for n. 
PV = nRT
n = PV/RT @ STP T= 0+273k; P = 1atm R = 0.821 L atm/molK
n = 1atm(56.2L)/0.821 L atm/molK(273k)
n = 2.50 mole
2.50 moles of Ar =39.984g of Ar/1mole of Ar