# physics

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what pressure (in atm) would be exerted by 76g of fluorine gas in a 1.5 litre vessel at -37 degrees Celsius?

• physics -

fluorine gas F₂=>
μ = 36 g/mol =36•10⁻³ kg/mol,
m= 0.076 kg,
V=1.5 L = 1.5•10⁻³ m³,
t= -37℃ = 236 K,

pV=mRT/ μ =>
p =mRT/ Vμ =0.076•8.31•236/1.5•10⁻³•36•10⁻³=
=2.76•10⁶ Pa = 27.23 atm

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