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what pressure (in atm) would be exerted by 76g of fluorine gas in a 1.5 litre vessel at -37 degrees Celsius?

  • physics -

    fluorine gas F₂=>
    μ = 36 g/mol =36•10⁻³ kg/mol,
    m= 0.076 kg,
    V=1.5 L = 1.5•10⁻³ m³,
    t= -37℃ = 236 K,

    pV=mRT/ μ =>
    p =mRT/ Vμ =0.076•8.31•236/1.5•10⁻³•36•10⁻³=
    =2.76•10⁶ Pa = 27.23 atm

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