posted by Anonymous .
If 10.5 g of hydrogen, H2, were mixed with 6.51 g of acetylene, C2H2, and allowed to react according to the following equation, what is the theoretical yield of ethane,C2H6 produced? If 7.00g of ethane, C2H6 were recovered at the end of the reaction , what is the percent yield.
This is a limiting reagent problem.
mols H2 = grams/molar mass
mols C2H2 = grams/molar mass.
Convert mols H2 to mols C2H6 using the coefficients in the balanced equation.
Do the same for mols C2H2.
It is likely that the two values will not agree which means one of them is wrong. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Using the smaller value convert to grams. g = mols x molar mass. This is the theoretical yield.
% yield = (actual yi8eld/theor yield)*100 = ?