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Can someone tell me if I am right? Factor by group 20x^212x=15x9 20x^2+3x+9 (4x+3)(5x3) answer 
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Andrew factored the expression 20x^312x^2+8x as 4x (5x^212x^2+8x). But when Melissa applied the distributive law and multiplied out 4x (5x^212x^2+8x), she got 20x^348x^3+32x^2; thus, Andrewâ€™s solution does not appear to check. … 
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Andrew factored the expression 20x^312x^2+8x as 4x(5x^212x^2+8x). But when Melissa applied the distributive law and multiplied out 4x(5x^212x^2+8x),she got 20x^348x^3+32x^2; thus, Andrew's solution does not appear to check. Why … 
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Can someone help me with this please. Andrew factored the expression 20x^312x^2+8x as 4x(5x^212x^2+8x) but when melissa applied the distributive law and multiplied out 4x(5x^212x^2+8x)she got 20x^348x^3+32x thus Andrews solution … 
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