A particle is projected vertically upwards with velocity of u.after t seconds particle is projected from some point with same velocity.How long does it take for the second particle to meet the first particle?
Stil wl b veloct of me nd -9.8m/s^2 for force of gravity
To determine how long it takes for the second particle to meet the first particle, we need to consider the motion of both particles.
Let's break down the problem:
1. The first particle is projected vertically upwards with a velocity of u.
2. After some time t, the second particle is projected from the same point with the same velocity u.
Now, let's find a way to compare the motion of both particles.
For the first particle:
1. The initial velocity (u) is in the upward direction.
2. The acceleration due to gravity (g) acts in the downward direction.
3. We can use the kinematic equation: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time.
For the second particle:
1. The initial velocity (u) is in the upward direction (same as the first particle).
2. The acceleration due to gravity (g) acts in the downward direction (same as the first particle).
Now, since both particles are experiencing the same acceleration due to gravity and have the same initial velocity, the time taken for both particles to meet will be the same.
Therefore, the time taken for the second particle to meet the first particle is equal to the original time t.