Algebra 2 ..

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Simplify.
1. (1/log base 3 of 60)+ (1/log base 4 of 60)+ (1/log base 5 of 60)

2. (log base 16 of x)+ ( log base 4 of x) + (log base 2 of x)=7

  • Algebra 2 .. -

    1/log_a(b) = log_b(a), so what you have is

    log_60(3) + log_60(4) + log_60(5)
    = log_60(3*4*5)
    = log_60(60)
    = 1

    since 16=2^4=4^2, you have

    log_16(x) + 2log_16(x) + 4log_16(x) = 7
    7log_16(x) = 7
    log_16(x) = 1
    x=16

  • Algebra 2 .. -

    -3 · -u · -7v + 8v - 6uv

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