algerba 1

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1. the sum of 3 numbers is 207. the 2nd # is 8 times the first, while the third is 3 less than the first. find the #s.

2. the sumof 3 numbers is 161. the second number is 6 times the first, and the third is 5 more than the second. find the #s.

Thanks so much!

  • algerba 1 -

    problem 1.
    let x = first number
    8x = second number
    x - 3 = third number

    x + (8x) + (x-3) = 207

    simply the equation and solve for x

    problem 2 is done the same way as the first one

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