posted by kelly .
1. the sum of 3 numbers is 207. the 2nd # is 8 times the first, while the third is 3 less than the first. find the #s.
2. the sumof 3 numbers is 161. the second number is 6 times the first, and the third is 5 more than the second. find the #s.
Thanks so much!
algerba 1 -
let x = first number
8x = second number
x - 3 = third number
x + (8x) + (x-3) = 207
simply the equation and solve for x
problem 2 is done the same way as the first one