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If 10.4 liters of O2 at STP are produced by the electrolysis of water, how many coulombs of charge were required?

  • chem -

    96,485 coulombs will produce 32/2 = 16 g O2 or 11.2L O2 @ STP. Therefore,
    C = 96,485 x 10.4/11.2 = ?

  • chem -

    i got 89593.2 but its wrong

  • chem -

    I suspect you are keying in too many significant figures. 10.4L limits you to 3 s.f.; you're keying in 6 s.f. You may also want to try using 96,500 for 1 Faraday to make that 3 s.f. also.

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